(9z^2+30z+25)/(9z^2+9z-10)

Simple and best practice solution for (9z^2+30z+25)/(9z^2+9z-10) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (9z^2+30z+25)/(9z^2+9z-10) equation:


D( z )

9*z^2+9*z-10 = 0

9*z^2+9*z-10 = 0

9*z^2+9*z-10 = 0

9*z^2+9*z-10 = 0

DELTA = 9^2-(-10*4*9)

DELTA = 441

DELTA > 0

z = (441^(1/2)-9)/(2*9) or z = (-441^(1/2)-9)/(2*9)

z = 2/3 or z = -5/3

z in (-oo:-5/3) U (-5/3:2/3) U (2/3:+oo)

(9*z^2+30*z+25)/(9*z^2+9*z-10) = 0

9*z^2+30*z+25 = 0

9*z^2+30*z+25 = 0

DELTA = 30^2-(4*9*25)

DELTA = 0

z = -30/(2*9)

z = -5/3 or z = -5/3

(z+5/3)^2 = 0

9*z^2+9*z-10 = 0

9*z^2+9*z-10 = 0

DELTA = 9^2-(-10*4*9)

DELTA = 441

DELTA > 0

z = (441^(1/2)-9)/(2*9) or z = (-441^(1/2)-9)/(2*9)

z = 2/3 or z = -5/3

(z+5/3)*(z-2/3) = 0

((z+5/3)^2)/((z+5/3)*(z-2/3)) = 0

z+5/3 = 0 // - 5/3

z = -5/3

z in { -5/3}

z belongs to the empty set

See similar equations:

| (-2/w+4)=(-5/2w+8)+2 | | 4^(3/2) | | (t^2-16)/(t-4) | | Wxy+6=a | | 7x+10+x+20+2x=180 | | -4(x+5)=-16 | | sqrt(3x^2-3)=3 | | 12(t-5)+6t=6(3t+3)-10 | | 1/x=(x/6)-(5/60) | | 8=(-12)+k/(-4) | | sqrt(x^2-25)=4 | | -4=7x+1/(-8) | | (-4k^4+14*3k^2)+(-3k^4-14k^2-8)= | | 8/5x-8=4/3 | | -3x+y=-23 | | y=7/8x+10 | | .16y+.02(y+2000)=1660 | | Y=-16x^2+22x+3 | | 4/(m-8)=8/2 | | F(x)=-16x^2+22x+3 | | (3/X+20)-(4/X-20)=4X/X^2-400 | | 2(6)-3y=9 | | 1/2s+4=6 | | (4r^3+3r^3)-(r^4-5r^3)= | | 5/3-1x/6=3x+5/4 | | 23.4-4.6-17.9= | | -5/7=c | | -5/1=x | | -3--4=x | | -7--2=x | | 3/2x+1/3=2x-3/4 | | 4x*4y=3 |

Equations solver categories